What is the reaction between $C u C l_{2}$ $CuCl_2$ , and aluminum metal to give copper metal and $A l C l_{3}$ $AlCl_3$ ?

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Answer 1 · 2016-04-21T06:47:19

$3 C u C l_{2} (a q) + 2 A l (s) \to 2 A l C l_{3} (a q) + 3 C u (s) ⏐ ↓$ $3CuCl_2(aq) +2Al(s) rarr 2AlCl_3(aq) + 3Cu(s)darr$

$A l \to A l^{3 +} + 3 e^{-}$ $Al rarr Al^(3+) + 3e^-$ ; oxidation.

$C u C l_{2} (a q) + 2 e^{-} \to C u (s) ⏐ ↓ + 2 C l^{-}$ $CuCl_2(aq) +2e^(-) rarr Cu(s)darr + 2Cl^-$ ; reduction.

We cross-mulitply to remove the electrons.

$3 C u C l_{2} (a q) + 2 A l (s) \to 2 A l C l_{3} (a q) + 3 C u (s) ⏐ ↓$ $3CuCl_2(aq) +2Al(s) rarr 2AlCl_3(aq) + 3Cu(s)darr$

A sheet of aluminum place in copper sulfate solution would rapidly acquire a coppery surface as the copper metal reduced.

What is the reaction between CuCl2CuCl_2, and aluminum metal to give copper metal and AlCl3AlCl_3?