Solve $10^{12 x + 2} = {(10^{10})}^{2 x - 1}$ $10^(12x+2) = (10^10)^(2x-1)$ ?

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Answer 1 · 2016-07-10T13:25:13

$x = \frac{3}{2}$ $x = 3/2$

${log}_{10} (12 x + 2) = {log}_{10} ((2 x - 1) \cdot 10) \to 12 x + 2 = 10 (2 x - 1)$ $log_{10}(12x+2)=log_{10}((2x-1)cdot 10)->12x+2=10(2x-1)$

Solving for $x$ $x$ gives

$x = \frac{3}{2}$ $x = 3/2$ which is feasible

Solve 1012x+2=(1010)2x−110^(12x+2) = (10^10)^(2x-1) ?