Question #a3009

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Question #a3009

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Answer 1 · 2016-12-28T03:06:19

${59.0}^{\circ}$ $59.0^@$ , rounded to one decimal place.

Explanation:

If $θ_{i}$ $theta_i$ is polarizing angle and $θ_{c}$ $theta_c$ is critical angle for a medium, taking other medium as air for which refractive index $= 1$ $=1$ , then the two are related via expression
$tan θ i = \frac{1}{{sin θ}_{c}}$ $tantheta i=1/sintheta_c$ ...........(1)
$\Rightarrow θ_{i} = {tan}^{- 1} (\frac{1}{{sin θ}_{c}})$ $=>theta_i=tan^-1(1/sintheta_c)$
Inserting given values we get
$θ_{i} = {tan}^{- 1} (\frac{1}{0.6})$ $theta_i=tan^-1(1/0.6)$
$θ_{i} = {59.0}^{\circ}$ $theta_i=59.0^@$ , rounded to one decimal place.

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Question #a3009

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