Question #fdebb
1 Answer
Sep 11, 2016
I got
Explanation:
# = e^(ax)[acos(bx)-bsin(bx)]#
And
Now, use trigonometry to get
So we have
# = (re^(ax))/sqrt(a^2+b^2)[bcos(bx)-asin(bx)]#
Setting the derivative above equal to this expression we get
Which leads immediately to