What is the $p H$ $pH$ of a solution of sulfuric acid of $5.98 \cdot m o l \cdot L^{- 1}$ $5.98molL^-1$ concentration?

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Answer 1 · 2016-06-22T04:24:18

$p H = - {log}_{10} [H_{3} O^{+}]$ $pH=-log_(10)[H_3O^+]$

$p H = - {log}_{10} [2 \times 5.98]$ $pH=-log_(10)[2xx5.98]$ $≅ - 1$ $~=-1$ .

Why did I multiply the given concentration by 2?

What is the pHpH of a solution of sulfuric acid of 5.98⋅mol⋅L−15.98*mol*L^-1 concentration?