Which of the following is a 2p orbital?

A)

B)

C)

D)

1 Answer
Aug 19, 2016

The 2p orbital is D.

  • A is an ns orbital, probably 3s or 4s, though it depends on their size.
  • B is a 3dz2 orbital.
  • C is a 3dxz orbital.

However, do not trust the image. B, C, and D are wrong because all the lobe signs are presented to be the same whereas they aren't.

The 3dz2 orbital ring is the opposite sign, the 3dxz has diagonal lobes of the same sign (yz and xy nodal planes), and the 2pz orbital's second lobe is the opposite sign.


The 2p orbital has:

  • n=2, for the principal quantum number. n can be one number in the set {1,2,3,...}.
  • l=1, for the angular momentum quantum number since l={0,1,2,3,...}{s,p,d,f,...}.

If you recall:

  • The total number of nodes (radial or angular regions of zero electron density) is equal to n1.
  • The total number of angular nodes (nodal planes or conic nodes) is l.
  • The total number of radial nodes is nl1.

Since l=1, there is one angular node, and since n1=1, it is the only node.

On either side of a nodal plane is a lobe of the opposite sign, and thus, there are two lobes on a 2p orbital. That means it has to be either B or D.

The B orbital has 2 conic nodes, which are angular nodes, and corresponds to how l=2 corresponds to a d orbital.

B is actually a 3dz2 orbital, like so:

Both lobes on B are actually the same sign, whereas it's the ring that is the opposite sign.

The 2p orbital is D.