Question #721f3

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Question #721f3

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Answer 1 · 2016-06-21T19:42:46

#9#

Explanation:

#=lim_(n->infty)(3^(n+2)-1)/(3^n+1) * (3^{-n})/(3^{-n})#
#= lim_(n->infty)(3^(2)-3^{-n})/(1+3^{-n})#
#= lim_(n->infty)(3^(2)-(1/3^n))/(1+(1/3^n)#
# = 9#

as #lim_{n \to \infty} 1/(3^{n}) = 0#

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Question #721f3

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