Question #cf901 Calculus Derivatives Average Rate of Change Over an Interval 1 Answer Alan P. Aug 1, 2016 #50.67796# years Explanation: An investment of #I# at an annual (compound) rate of #r# for a period of #n# years yields #color(white)("XXX")v=I*(1+r)^n# We are told #color(white)("XXX")v=2467174# (forints) #color(white)("XXX")r=7%=0.07# and #color(white)("XXX")I=80000# (forints) Therefore #color(white)("XXX")80000 * (1.07)^n=2467174# or #color(white)("XXX")(1.07)^n=2467174/80000# Taking the #log_(1.07)# of both sides (use a calculator) #color(white)("XXX")n=log_1.07 (2467174/80000)=50.67796# Answer link Related questions How do you find the average rate of change of a function from graph? How do you find the average rate of change of a function between two points? How do you find the average rate of change of #f(x) = sec(x)# from #x=0# to #x=pi/4#? How do you find the average rate of change of #f(x) = tan(x)# from #x=0# to #x=pi/4#? How do you find the rate of change of y with respect to x? How do you find the average rate of change of #y=x^3+1# from #x=1# to #x=3#? What is the relationship between the Average rate of change of a fuction and derivatives? What is the difference between Average rate of change and instantaneous rate of change? What does the Average rate of change of a linear function represent? What is the relationship between the Average rate of change of a function and a secant line? See all questions in Average Rate of Change Over an Interval Impact of this question 1820 views around the world You can reuse this answer Creative Commons License