#f(x) = 2x^4-3x^3-5x^2+9x-3# Given that #sqrt(3)# forms two of the roots, find all the roots of the polynomial?
2 Answers
The roots of the polynonial are:
Explanation:
The roots of the polynonial are those values of
Since
The question tells us the
Long dividing
This factorises as:
Hence the two remaining roots are:
Therefore the four roots of
Explanation:
There appears to be error in posting the question.
As mentioned the two zeros are not
I found that the two zeros must be
.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.--.-.-.
Given equation is
Given that two of its zeros are
If we divide the equation (1) by the above quadratic by long division method we get another quadratic which is a factor of equation (1)
To find factors of second quadratic we use split the middle term method
Setting each factor