Rational Zeros
Key Questions
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Answer:
See explanation...
Explanation:
The rational zeros theorem can be stated:
Given a polynomial in a single variable with integer coefficients:
a_n x^n + a_(n-1) x^(n-1) + ... + a_0 with
a_n != 0 anda_0 != 0 , any rational zeros of that polynomial are expressible in the formp/q for integersp, q withp a divisor of the constant terma_0 andq a divisor of the coefficienta_n of the leading term.Interestingly, this also holds if we replace "integers" with the element of any integral domain. For example it works with Gaussian integers - that is numbers of the form
a+bi wherea, b in ZZ andi is the imaginary unit. -
The Rational Zeros Theorem states: If
P(x) is a polynomial with integer coefficients and ifp/q is a zero ofP(x) , (P(p/q) = 0 ), thenp is a factor of the constant term ofP(x) and q is a factor of the leading coefficient of P(x) . -
Answer:
See explanation...
Explanation:
A polynomial in a variable
x is a sum of finitely many terms, each of which takes the forma_kx^k for some constanta_k and non-negative integerk .So some examples of typical polynomials might be:
x^2+3x-4 3x^3-5/2x^2+7 A polynomial function is a function wholse values are defined by a polynomial. For example:
f(x) = x^2+3x-4 g(x) = 3x^3-5/2x^2+7 A zero of a polynomial
f(x) is a value ofx such thatf(x) = 0 .For example,
x=-4 is a zero off(x) = x^2+3x-4 .A rational zero is a zero that is also a rational number, that is, it is expressible in the form
p/q for some integersp, q withq != 0 .For example:
h(x) = 2x^2+x-1 has two rational zeros,
x=1/2 andx=-1 Note that any integer is a rational number since it can be expressed as a fraction with denominator
1 . -
You can use the rational root theorem:
Given a polynomial of the form:
a_0x^n+a_1x^(n-1)+...+a_n witha_0,...,a_n integers,all rational roots of the form
p/q written in lowest terms (i.e. withp andq having no common factor) will satisfy.p | a_n andq | a_0 That is
p is a divisor of the constant term andq is a divisor of the coefficient of the highest order term.This gives you a finite number of possible rational roots to try.
For example, the rational roots of
6x^4-7x^3+x^2-7x-5=0 must be of the form
p/q wherep is+-1 or+-5 and
q is1 ,2 ,3 or6 .You can try substituting each of the possible combinations of
p andq asx=p/q into the polynomial to see if they work.In fact the only rational roots it has are
-1/2 and5/3 .Once you have found one root, you can divide the polynomial by the corresponding factor to simplify the problem.
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To find the zeroes of a function,
f(x) , setf(x) to zero and solve.
For polynomials, you will have to factor.For example: Find the zeroes of the function
f(x) = x^2+12x+32 First, because it's a polynomial, factor it
f(x) = (x+8)(x+4) Then, set it equal to zero
0 = (x+8)(x+4) Set each factor equal to zero and the answer is
x=-8 andx=-4 .*Note that if the quadratic cannot be factored using the two numbers that add to this and multiple to be this method, then use the quadratic formula
(-b +- sqrt(b^2-4ac))/(2a) to factor an equation in the form of
ax^2+bx+c .