Upper and Lower Bounds

Key Questions

  • How do I find the upper bound of a function?

    Answer:

    Best way is to find it from the graph of the function.

    Explanation:

    The range of a function can be found in many ways , best way and a concrete way is by plotting its graph and determining.

    How you draw the graph depends on you, a generic way is by differentiating the function to get the critical points or the points of maxima or minima . Then you double differentiate the function to see if the critical point is a maxima or minima by putting the critical point in the double differentiated function. If the output is positive then is a minima , if its negative then its a maxima and if its zero then the test fails,we have to go for high derivative tests. The global maxima points give you the upper bound.

    Also we can determine the point of inflection for the given curve to determine the convexity or concavity changes of the given function to make the graph more precise .

    Thus, having plotted the graph we can tell the upper bound of the function by merely looking at the maximum value of y for all values of x.

    Useful links:

    coursera

    examples

    Deepesh Pandey · 1 · Mar 4 2018
  • How do I determine whether a function is bounded?

    A function f is bounded in a subset U of its domain if there exist constants M, m in RR such that

    m<=f(x)<=M, for all x in U.

    For example,

    1. f(x)=sin(x) is bounded in RR because

    -1<=sin(x)<=1, for all x in RR.
    2. f(x)=x^2 is bounded in [0,1] because

    0<=x^2<=1, for all x in [0,1].

    Reginaldo D. · 1 · Oct 27 2014
  • How do I find the lower bound of a function?

    Answer:

    See below.

    Explanation:

    First of all, let's get rid of infinities: a function can tend to \pm\infty either at the extreme points of its domain or because of some vertical asymptote.

    So, you should first of all check

    lim_{x \to x_0} f(x)

    for every point x_0 at the boundary of the domain. For example, if the domain is (-\infty,\infty), you should check

    lim_{x \to \pm\infty} f(x)

    If the domain is like \mathbb{R}\setminus{2} you should check

    lim_{x \to \pm\infty} f(x),\qquad lim_{x \to 2^\pm} f(x)

    and so on. If any of these limits is -\infty, the function has no finite lower bound.

    Else, you can check the derivative: when you set f'(x)=0, you will find points of maximum of minimum. For every x which solves f'(x)=0, you should compute f''(x). If f''(x)>0, the point is indeed a minumum.

    Now, in the most general case, you have a collection of points x_1,...,x_n such that

    f'(x_i)=0,\qquad f''(x_i)>0 for every i=1,.., n

    Which means that they are all local minima of your function. The lower bound of the function, i.e. the global minimum, will be the smallest image of those points: you just need to compare

    f(x_1), ..., f(x_n), and choose the smallest one.

    KillerBunny · 1 · Jun 23 2018
  • What is a bound of a function?

    If real numbers L and U satisfy the inequalities

    L le f(x) le U,

    for all x in the domain of f, then L is a lower bound of f and U is an upper bound of f.

    I hope that this was helpful.

    Wataru · 1 · Nov 1 2014

Questions

Real Zeros of Polynomials