Question #d3486

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Answer 1 · 2016-07-20T13:07:16

#color(brown)(y=-54/22)#

Assumption: The equation is meant to be
#2/3y-(-3-y/18)=-y/2#

First dealing with the bracket. The minus outside the bracket is basically instructing that everything inside the bracket is multiplied by -1 giving.

#color(brown)(2/3 y+3+y/18" "=" "-y/2)#

Subtract #color(blue)(3)# from both sides

#color(brown)(2/3 y+y/18+3color(blue)(-3)" "=" "-y/2color(blue)( -3))#

#color(brown)(2/3 y+y/18" "=" "-y/2-3)#

Add #color(blue)(y/2)# to both sides

#color(brown)(2/3 y+y/18color(blue)(+y/2)" "=" "color(blue)(y/2)-y/2-3)#

#color(brown)((2y)/3+y/18+y/2" "=" "-3#

Write over a common denominator

#color(brown)((12y+y+9y)/18" "=" "-3)#

Multiply both sides by 18

#color(brown)(22y=-54)#

Divide both sides by 22

#color(brown)(y=-54/22)#