Question

Question #e120d

Answer 1

Move all of the constants to one side of the equation with algebraic operations for general expression equal to x. This a function, not a single value.

Explanation:

You find ‘y’ for any given ‘x’ by putting x into the equation and solving it.
`y = -3sqrt(x+4) + 6 ; y – 6 = -3sqrt(x+4) ; (y-6)/3 = sqrt(x+4) ; (y/3) – 2 = sqrt(x+4)`
Now, square both sides:
`(y^2)/9 – (4/3)y + 4 = x + 4`
`(y^2)/9 – (4/3)y = x`