Question #c4a4c Calculus Graphing with the Second Derivative Determining Points of Inflection for a Function 1 Answer Jim H Dec 16, 2016 Yes. Explanation: Let #f(x) = {(-sqrt(1-x)+2,"if", x <= 1),(-(x-1)^2+2,"if",x>1):}#. #f# is concave up on #(-oo,1)# and concave down on #(1,oo)# so #(1.2)# is an inflection point. It is also a maximum point. Here is the graph: (Sorry the image is a little small.) Answer link Related questions How do you find the inflection points for the function #f(x)=8x+3-2 sin(x)#? How do you find the inflection point of a cubic function? How do you find the inflection point of a logistic function? What is the inflection point of #y=xe^x#? How do you find the inflection points for the function #f(x)=x^3+x#? How do you find the inflection points for the function #f(x)=x/(x-1)#? How do you find the inflection points for the function #f(x)=x/(x^2+9)#? How do you find the inflection points for the function #f(x)=xsqrt(5-x)#? How do you find the inflection points for the function #f(x)=e^sin(x)#? How do you find the inflection points for the function #f(x)=x-ln(x)#? See all questions in Determining Points of Inflection for a Function Impact of this question 1301 views around the world You can reuse this answer Creative Commons License