Question #97503

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Answer 1 · 2016-08-02T02:53:52

Here's what I get.

The general equation for the dissociation of a carboxylic acid is

${R-COOH + H}_{2} O ⇌ {R-COO}^{-} + H_{3} O^{+}$ $"R-COOH + H"_2"O" ⇌ "R-COO"^"-" + "H"_3"O"^+$

All we have to do is write the structure for the $R$ $"R"$ group of the carboxylic acid..

Acrylic acid

The dissociation equation is

$H_{2} {C=CH-COOH + H}_{2} O ⇌ H_{2} {C=CH-COO}^{-} + H_{3} O^{+}$ $"H"_2"C=CH-COOH + H"_2"O" ⇌ "H"_2"C=CH-COO"^"-" + "H"_3"O"^+$

Lactic acid

The dissociation equation is

${CH}_{3} {CH(OH)-COOH + H}_{2} O ⇌ {CH}_{3} {CH(OH)-COO}^{-} + H_{3} O^{+}$ $"CH"_3"CH(OH)-COOH + H"_2"O" ⇌ "CH"_3"CH(OH)-COO"^"-" + "H"_3"O"^+$