Question

Question #c9f53

Answer 1

`""_(color(white)(a)6)^14"C"`

Explanation:

The problem gives you the isotope's atomic number, which means that you know how many protons it contains in its nucleus.

In this case, your isotope has an atomic number

`Z=6`

which tells you that you have `6` protons inside the nucleus. You also know that the isotope has `8` neutrons, which means that you have all the information that you need in order to calculate its mass number, `A`

`color(blue)(|bar(ul(color(white)(a/a)A = Z + "no. of neutrons" color(white)(a/a)|)))`

In this case, you have

`A = 6 + 8 = 14`

Now, grab a periodic table and look for the element that has an atomic number equal to `6`. You'll find it located in period 2, group 14 `->` carbon, `"C"`.

You know that you're dealing with an isotope of carbon that has `8` neutrons. To write it using isotope notation, add the mass number to the upper left of the chemical symbol and the atomic number to the lower left.

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You will have

`""_(color(white)(a)6)^14"C" ->` carbon-14