Question #26ccf

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Question #26ccf

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Answer 1 · 2016-08-02T14:58:02

$n = 1$ $n=1$

Explanation:

Kinematic equation for free fall under gravity is given by
$h = u t + \frac{1}{2} g t^{2}$ $h=ut+1/2g t^2$ .
$u and t$ $u and t$ are initial velocity and time of fall to reach ground respectively.

Height of $9 t h$ $9th$ storeys of the building $h$ $h$ , is found by inserting given values
$h = 0 \times 3 + \frac{1}{2} \times 10 \times 3^{2} = 45 m$ $h=0xx3+1/2xx10xx3^2 =45 m$
Height of each storey $= \frac{45}{9} = 5 m$ $=45/9=5m$
Height dropped in first second is
$h_{1} = 0 \times 3 + \frac{1}{2} \times 10 \times 1^{2} = 5 m$ $h_1=0xx3+1/2xx10xx1^2 =5 m$
Now height dropped in first second $5 m$ $5m$
$= n \times height of each storey$ $=nxx"height of each storey"$
$\Rightarrow n = 1$ $=>n=1$

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Question #26ccf

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