Question #05592

1 Answer
P dilip_k
Aug 27, 2016

Now we can proceed framing ICE table

N2(g) + 3H2(g) ⇌ 2NH3(g)

I 0.2 mol 0.6 mol 0 mol

C −0.2⋅40%mol −0.6⋅40%mol +0.16mol

E 0.12 mol 0.36 mol 0.16mol

As 40% reactants react

N2→reacted 0.2⋅40%=0.08 mol,Leaving 0.12 mol

H2→reacted 0.6⋅40%=0.24 mol, Leaving 0.36 mol

NH3→produced 0.16 mol ( twice the no.of moles of nitrogen reacted.)

Initial total number of moles = 0.8mol

Final total number of moles =0.12+0.36+0.16=0.64 mol

As the temperature and pressure remain unaltered the ratio of final and initial volumes of gases will be equal to the ratio of their respective total no. of moles.So the ratio becomes

0.64:0.80=4:5

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