Question #d1a37

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Question #d1a37

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Answer 1 · 2017-10-01T21:44:40

I got $55.6 m$ $55.6m$

Explanation:

I would impose that the initial velocity is zero (....drops) so I use the relationship:
$v_{f}^{2} = v_{i}^{2} + 2 a (y_{f} - y_{i})$ $v_f^2=v_i^2+2a(y_f-y_i)$
Where:
$v_{i} = 0$ $v_i=0$ the initial velocity;
$y_{f} = 0$ $y_f=0$
$g = - 9.8 \frac{m}{s^{2}}$ $g=-9.8m/s^2$
$v_{f} = 33 \frac{m}{s}$ $v_f=33m/s$
So we get:
$33^{2} = 0^{2} - 2 \cdot 9.8 (0 - y_{i})$ $33^2=0^2-2*9.8(0-y_i)$
$1089 = 19.6 y_{i}$ $1089=19.6y_i$
So:
$y_{i} = \frac{1089}{19.6} = 55.56 \approx 55.6 m$ $y_i=1089/19.6=55.56~~55.6m$

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Question #d1a37

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