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Answer 1 · 2016-09-09T12:49:24

$LPG contains 60% propane and 40% butane$ $"LPG contains 60% propane and 40% butane "$

$:."10L LPG contains 6L propane and 4L butane "$

The balanced equations of the gaseous combustion reactions

$C_3H_8(g)+5O_2(g) -> 3CO_2(g)+4H_2O(g).....(1)$

$2C_4H_10(g)+13O_2(g)-> 8CO_2(g)+10H_2O(g)......*2)$

By equation(1)

1L Propane on combustion produces 3L $CO_2(g)$

$"6L Propane on combustion produces "(3xx6)=18L" " CO_2(g)$

By equation(2)

2L Butane on combustion produces 8L $CO_2(g)$

$"4L Butane on combustion produces "(8xx4)/2=16L" " CO_2(g)$

So the total volume of $CO_2(g)$ added on combustion of 10 L LPG will be (18+16)=34L