If #e^4x-e=0# what is #x#? Alternately, if #e^(4x)-e=0# what is #x#?

2 Answers
Sep 19, 2016

#x=e^(-3)#

Explanation:

Given
#color(white)("XXX")e^4x-e=0#
then
#color(white)("XXX")e^4x=e#
and (after dividing both sides by #e^4#
#color(white)("XXX")x=e^(-3)#

(Using a calculator for an approximation: #e^(-3) = 0.049787068 #)

Sep 19, 2016

#x=1/4#

Explanation:

#e^(4x)-e=1 " and adding e to both sides"#

#e^(4x)=e^1" and since the bases (e) are equal, then"#

#4x=1rArrx=1/4#