Question

Question #127ef

Answer 1

I found: `lambda=6xx10^-7m`

Explanation:

You may remember the fundamental relationship between frequency, `f`, speed of light (in vacuum), `c=3xx10^8m/s` (from literature) and wavelength `lambda` as:
`c=lambda*f`

which is actually a very broad "relative" to the more common `"velocity"="distance"/"time"` relation.

where frequency has units of `1/"time"`

With your data:

`3xx10^8=lambda*5xx10^14`

rearranging:

`lambda=c/f=(3xx10^8)/(5xx10^14)=6xx10^-7m`

you can check the units from:
`lambda=c/f` as:
`lambda=(m/s)/(1/s)=m/s*s=m`