Question #fe1a9

1 Answer
P dilip_k
Oct 12, 2016

As the ball is thrown horizontally with velocity #u=12m/s# its initial vertical component will be zero and the time taken for free fall of height, #h= 28m# under gravity will be its time (t) required to land.

So #h=1/2*g*t^2#
#=>t=sqrt((2h)/g)=sqrt(2*28)/9.8~~2.39s#

During this time of fall the horizontal component will remain undiminished,supposing no resistance of air.So the horizontal diatance traversed during this time of fall will be

#S=uxxt=12xx2.39m~~28.68m#

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