Question #0d32e

1 Answer
P dilip_k
Oct 18, 2016

In first oxide #"Oxygen"->20% and "Metal"->80%#

Here Ratio of

#"Oxygen":"Metal"=1:4#

In 2nd oxide #"Oxygen"->11.1% and "Metal"->88.9%#

Here Ratio of

#"Oxygen":"Metal"=1:8#

So ratio of masses of metal combining with same mass of Oxygen in two oxides will be #=4:8=1:2# which is a ratio of simple whole number .So the law of multiple proportion is followed by the given data

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