How you simplify $log (8) + log (18)$ $log(8) + log(18)$ ?

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Answer 1 · 2016-12-12T00:35:14

$4 log 2 + 2 log 3$ $4log2 + 2log3$

$log 8 = log (2^{3}) = 3 log 2$ $log8 = log(2^3) = 3log2$

$log (18) = log (9 \times 2) = log 9 + log 2$ $log(18) = log(9 xx 2) = log9 + log2$

$log (9) = log (3^{2}) = 2 log 3$ $log(9) = log(3^2) = 2log3$

Putting this together, we have:

$log 8 + log 18 = 2 log 3 + log 2 + 3 log 2 = 4 log 2 + 2 log 3$ $log8 + log18 = 2log3 + log2 + 3log2 = 4log2 + 2log3$

This is as good as we can get it.

Hopefully this helps!

How you simplify log(8)+log(18)log(8) + log(18)?