Question #f5014

1 Answer
Krzysztof S.
Nov 8, 2016

#E_(mol)=21.13 *10^5J#

Explanation:

1 mol = Avogadro's number = #=6,02* 10 ^23# photons
Energy 1 photon #E=h* nu= hc/lambda#
#lambda=565 nm=565 *10^-9m # wave length
#h=6.62 *10^-34J*s# Planck constant
#c=3* 10^9m/s # speed of light

#E(dim)= Js*m/s* 1/m=J#
#E=3.51*10^-18 J#

#E _(mol) =N_A*E #
#E _(mol)=6.02*10^23*3.51*10^-18=21.13 *10^5J#

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