Question #40306

1 Answer
Nov 16, 2016

The mass of the man #=76kg#
The downward gravitational force on him
#=76xxgN=76xx9.8N=744.8N#

The mass of the Parachute #=5.5kg#
The downward gravitational force on it
#=5.5xxgN=5.5xx9.8N=53.9N#

So total downward gravitational pull
#F_gdarr = (744.8+ 53.9)N = 798.7N#

The net downward acceleration on the system is #2.6ms^-2#

So the net downward force

#F_ndarr=(76+5.5)xx2.6=211.9N#

Now

#F_ndarr=F_gdarr-F_"air"uarr#

#=>F_"air"uarr=F_gdarr-F_ndarr#

#=>F_"air"uarr=798.7-211.9=586.8N#

(a) The upward force exerted on the open parachute by the air#=F_"air"uarr=586.8N#

(b) The downward force exerted by the person on the parachute #=744.8N#