If #541g# of calcium is reacted with water to give a #1L# volume of solution, what is #[Ca^(2+)]#?

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Answer 1 · 2016-11-26T01:38:21

#"Molarity"="Moles of solute"/"Volume of solution"#

And thus #"Molarity"=(541*cancelg)/(40.00*cancelg*mol^-1)xx1/(1*L)# #># #10*mol*L^-1#.

Dimensionally you get an answer in #1/(L*mol^-1)=mol*L^-1#, because #1/(mol^-1)=1/(1/(mol))=mol#, as required.

If #541*g# of calcium is reacted with water to give a #1*L# volume of solution, what is #[Ca^(2+)]#?