Question #f6ab2

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Answer 1 · 2016-11-27T15:15:46

$f (- 10) = - \frac{5}{42}$ $f(-10) = -5/42$

Substitute -10 for each occurrence of $x$ $x$ in the function:

$f (- 10) = \frac{- 10}{- 10^{2} - 16}$ $f(-10) = (-10)/(-10^2 - 16)$

$f (- 10) = \frac{- 10}{100 - 16}$ $f(-10) = (-10)/(100 - 16)$

$f (- 10) = - \frac{10}{84}$ $f(-10) = -10/84$

$f (- 10) = \frac{2}{2} \cdot - \frac{5}{42}$ $f(-10) = 2/2 * -5/42$

$f (- 10) = - \frac{5}{42}$ $f(-10) = -5/42$