Question #1d33e

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Question #1d33e

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Answer 1 · 2016-12-06T07:03:03

$E$ $E$ = $3.146 \cdot 10^{6} J$ $3.146*10^6J$

Explanation:

$E$ $E$ photon = $\frac{h c}{λ}$ $(hc)/(lambda)$

$E$ $E$ photon = $\frac{6.626 \cdot 10^{- 34} J \cdot s \cdot 2.998 \cdot 10^{8} m \cdot s^{- 1}}{3 \cdot 10^{- 8} m}$ $(6.626*10^-34J*s*2.998*10^8m*s^-1)/(3*10^-8m$

$E$ $E$ photon = $5.227 \cdot 10^{- 18} J$ $5.227*10^-18J$

$(5.227 \cdot 10^{- 18} J)$ $(5.227*10^-18J)$ per photon $\cdot (6.02 \cdot 10^{23})$ $*(6.02*10^23)$ photon =

$E$ $E$ = $3.146 \cdot 10^{6} J$ $3.146*10^6J$

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