Question #26591

↳Redirected from "What are molarity, molality, and normality?"
1 Answer
Kayla
Dec 17, 2016

#lambda = 4.75xx10^4 m#

Explanation:

To answer this question, we can use the wave equation formula:

![www.antonine-education.co.uk)

Where #lamda# is the wavelength and it has units of meters. #c# is the speed of light and it has a value of #3.0xx10^8 m/s#. #f# represents the frequency and it has units of Hertz or reciprocal seconds (#1/s#).

We know the frequency, #f# and the speed of light since that is a constant. All we have to do is plug in the known values and solve for #lambda#:

#lambda = (3.0xx10^8 m/cancel"s")/((6.21xx1018)/cancel"s")#

#lambda = (3.0xx10^8 m/cancel"s")/(6321.78/cancel"s")#

#lambda = 4.75xx10^4 m#

Related questions
See all questions in Calculations with wavelength and frequency
Impact of this question
2565 views around the world
You can reuse this answer
Creative Commons License