Question

Question #da6e2

Answer 1

I got `x=3`

Explanation:

We can write:
`log(x-1)^2=log(x+1)`
The logs are equal if the arguments are equal:
So, we must have:
`(x-1)^2=(x+1)`
`x^2-2x+1=x+1`
`x^2-3x=0`
Let us rearrange:
`x(x-3)=0`
This will give us two solutions:
`x_1=0` not acceptable because it would make the argument of the first log negative.
`x_2=3`