What are necessary and sufficient conditions for a linear polynomial to be a factor of a given polynomial?

1 Answer
Jun 7, 2017

See explanation...

Explanation:

Suppose you are given a polynomial:

f(x) = a_n x^n + a_(n-1) x^(n-1) +...+ a_1 x + a_0

and a potential linear factor:

px+q

where all of a_n, a_(n-1),..., a_0, p and q are integers.

Then px+q can only be a factor of f(x) if p is a factor of a_n and q is a factor of a_0.

This immediately allows you to rule out many possibilities, but is not a sufficient condition.

What is sufficient is if f(-q/p) = 0.

In fact this last condition is both necessary and sufficient regardless of whether the coefficients are integers, rational, real or even complex numbers.