If a $34.7 \cdot L$ $34.7*L$ quantity of dihydrogen gas reacts with stoichiometric $C l_{2}$ $Cl_2$ , what VOLUME of $H C l (g)$ $HCl(g)$ will result under standard conditions?

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If a $34.7 \cdot L$ $34.7*L$ quantity of dihydrogen gas reacts with stoichiometric $C l_{2}$ $Cl_2$ , what VOLUME of $H C l (g)$ $HCl(g)$ will result under standard conditions?

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Answer 1 · 2017-02-16T17:02:28

Look at the stoichiometry.........approx. $70 \cdot L$ $70*L$ of $hydrogen chloride$ $"hydrogen chloride"$ gas will result.

Explanation:

$Look at the stoichiometry.........$ $"Look at the stoichiometry........."$

$H_{2} (g) + C l_{2} (g) \to 2 H C l (g)$ $H_2(g) + Cl_2(g) rarr 2HCl(g)$

If a $34.7 \cdot L$ $34.7*L$ volume of $dihydrogen$ $"dihydrogen"$ react, then under equiv conditions of temperature and pressure, a $69.4 \cdot L$ $69.4*L$ volume of $hydrogen chloride$ $"hydrogen chloride"$ gas will result. This is explicitly specified by the stoichiometric equation as given.

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If a $34.7 \cdot L$ $34.7*L$ quantity of dihydrogen gas reacts with stoichiometric $C l_{2}$ $Cl_2$ , what VOLUME of $H C l (g)$ $HCl(g)$ will result under standard conditions?

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If a 34.7⋅L34.7*L quantity of dihydrogen gas reacts with stoichiometric Cl2Cl_2, what VOLUME of HCl(g)HCl(g) will result under standard conditions?

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If a $34.7 \cdot L$ $34.7*L$ quantity of dihydrogen gas reacts with stoichiometric $C l_{2}$ $Cl_2$ , what VOLUME of $H C l (g)$ $HCl(g)$ will result under standard conditions?