How do the ionic radii of $F e^{2 +}$ $Fe^(2+)$ and $F e^{3 +}$ $Fe^(3+)$ compare?

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How do the ionic radii of $F e^{2 +}$ $Fe^(2+)$ and $F e^{3 +}$ $Fe^(3+)$ compare?

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Answer 1 · 2017-02-13T03:56:31

What do you think? I am hardly sticking my neck out if I predict that the ionic radii of the $ferric ion$ $"ferric ion"$ IS MARKEDLY LESS than that of the $ferrous ion$ $"ferrous ion"$ . Why?

Explanation:

You know (i) that the atom is mostly empty space; and (ii) that atomic radius can be estimated on the basis of the valence electrons. In the case of $ferric ion$ $"ferric ion"$ you have removed 3 of these valence electrons, and the ionic radius should decrease appropriately. And now this is your job: find estimates for atomic and ionic radius on the web, and see how they compare.

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How do the ionic radii of $F e^{2 +}$ $Fe^(2+)$ and $F e^{3 +}$ $Fe^(3+)$ compare?

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How do the ionic radii of Fe2+Fe^(2+) and Fe3+Fe^(3+) compare?

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How do the ionic radii of $F e^{2 +}$ $Fe^(2+)$ and $F e^{3 +}$ $Fe^(3+)$ compare?