Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

Question #0166b

1 Answer

Feb 22, 2017

$( 1-sin^4x+cos^4x) / (cos^2xsin^2x)$

$=( 1-(sin^4x-cos^4x)) / (cos^2xsin^2x)$

$=( 1-(sin^2x-cos^2x)(sin^2x+cos^2x))/ (cos^2xsin^2x)$

$=( 1-sin^2x+cos^2x) / (cos^2sin^2x)$

$=( cos^2x+cos^2x) / (cos^2sin^2x)$

$=( 2cos^2x) / (cos^2sin^2x)$

$=2 / sin^2x=2csc^2x$

Related questions

See all questions in Fundamental Identities

Impact of this question

1600 views around the world

You can reuse this answer
Creative Commons License