Question #586ed

1 Answer
Jim G.
Dec 11, 2017

#x~~0.668" to 3 dec. places"#

Explanation:

#5e^(2x)+1=20#

#rArr5e^(2x)=19#

#rArre^(2x)=19/5#

#•color(white)(x)logx^nhArrnlogx#

#"take the ln (natural log ) of both sides"#

#lne^(2x)=ln(19/5)#

#rArr2xcancel(lne)^1=ln(19/5)#

#rArrx=(ln(19/5))/2~~0.688" to 3 dec. places"#

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