Question #04063 Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Cesareo R. Mar 3, 2017 x=10.3log(111) Explanation: 1001000=110=11+999e−0.3x so 1+999e−0.3x=10→e−0.3x=9999=1111 finally −0.3x=log(1111)=−log(111)→x=10.3log(111) Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9x−4=81? How do you solve logx+log(x+15)=2? How do you solve the equation 2log4(x+7)−log4(16)=2? How do you solve 2logx4=16? How do you solve 2+log3(2x+5)−log3x=4? See all questions in Logarithmic Models Impact of this question 1092 views around the world You can reuse this answer Creative Commons License