Question

Question #04063

Answer 1

`x=1/0.3 log(111)`

Explanation:

`100/1000=1/10=1/(1+999e^(-0.3x))` so

`1+999e^(-0.3x)=10->e^(-0.3x)=9/999=1/111`

finally

`-0.3x=log(1/111)=-log(111)->x=1/0.3 log(111)`