Question #3ba38

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Answer 1 · 2017-04-12T17:26:43

#z=-1/(t+C)#

Integrate both sides.

#int (dz)/z^2 = -1/z+C_1#

#int dt = t +C_2#.

So,

#-1/z +C_1 = t +C_2#

Let's combine the two arbitrary constants into one.

#-1/z = t +C#.

Now, solve for #z#.

#z=-1/(t+C)#