Question #4d789

1 Answer
Mar 3, 2017

4/13.413.

Explanation:

Suppose, Event D=D=Pat picked a Diamond Card from pack, and,

Event J=J=pat picked a Jack from pack.

Then, Reqd. Prob.

=P(DuuJ)=P(D)+P(J)-P(DnnJ)................(star).

(star1):P(D):-

There are 52 cards in a pack, out of which 1 card can be

selected in 52 ways. Hence, the total no. n of outcomes is,

n=52.

There are 13 Diamond Cards in a pack, so, 1 such card can

be selected in 13 ways. Hence, the total no. r of outcomes

favorable to the occurance of the event D is, r=13.

:. P(D)=r/n=13/52.....................(star1).

(star2): P(J):- "Similarly, "P(J)=4/52.................(star2).

(star3): P(DnnJ):-

Event DnnJ=Card picked is a Jack of Diamond.

As discussed above, we have, P(DnnJ)=1/52........(star3).

Utilising (star1), (star2) and (star3) in (star), we have,

"The Reqd. Prob.="13/52+4/52-1/52=16/52=4/13.

Enjoy Maths.!