Suppose, Event D=D=Pat picked a Diamond Card from pack, and,
Event J=J=pat picked a Jack from pack.
Then, Reqd. Prob.
=P(DuuJ)=P(D)+P(J)-P(DnnJ)................(star).
(star1):P(D):-
There are 52 cards in a pack, out of which 1 card can be
selected in 52 ways. Hence, the total no. n of outcomes is,
n=52.
There are 13 Diamond Cards in a pack, so, 1 such card can
be selected in 13 ways. Hence, the total no. r of outcomes
favorable to the occurance of the event D is, r=13.
:. P(D)=r/n=13/52.....................(star1).
(star2): P(J):- "Similarly, "P(J)=4/52.................(star2).
(star3): P(DnnJ):-
Event DnnJ=Card picked is a Jack of Diamond.
As discussed above, we have, P(DnnJ)=1/52........(star3).
Utilising (star1), (star2) and (star3) in (star), we have,
"The Reqd. Prob.="13/52+4/52-1/52=16/52=4/13.
Enjoy Maths.!
