Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

Question #f0b82

1 Answer

Aug 6, 2017

#d/dx(logx^2-cot2x) = 2/x+2csc^2 2x#

Explanation:

#d/dx(logx^2-cot2x) = d/dx(logx^2)-d/dx(cot2x)#

#d/dx(logx^2) = ((x^2)')/x^2 = (2x)/x^2=2/x#

#-d/dx(cot2x) = --2csc^2 2x= 2csc^2 2x#

#therefore d/dx(logx^2-cot2x) = 2/x+2csc^2 2x#

Related questions

What is the limit definition of the derivative of the function #y=f(x)# ?
Ho do I use the limit definition of derivative to find #f'(x)# for #f(x)=3x^2+x# ?
How do I use the limit definition of derivative to find #f'(x)# for #f(x)=sqrt(x+3)# ?
How do I use the limit definition of derivative to find #f'(x)# for #f(x)=1/(1-x)# ?
How do I use the limit definition of derivative to find #f'(x)# for #f(x)=x^3-2# ?
How do I use the limit definition of derivative to find #f'(x)# for #f(x)=1/sqrt(x)# ?
How do I use the limit definition of derivative to find #f'(x)# for #f(x)=5x-9x^2# ?
How do I use the limit definition of derivative to find #f'(x)# for #f(x)=sqrt(2+6x)# ?
How do I use the limit definition of derivative to find #f'(x)# for #f(x)=mx+b# ?
How do I use the limit definition of derivative to find #f'(x)# for #f(x)=c# ?

See all questions in Limit Definition of Derivative

Impact of this question

1279 views around the world

You can reuse this answer
Creative Commons License