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Question #f3a16

1 Answer

Mar 6, 2017

The right answer is #a) 17#

Explanation:

We can solve directly the integral using the power rule:

#int_(-oo)^0 dx/(x-1)^2 = [-1/(x-1)]_(-oo)^0#

#int_(-oo)^0 dx/(x-1)^2 = 1 + lim_(x->-oo) 1/(x-1) = 1#

So:

#int_(-oo)^0 17/(x-1)^2dx = 17#

and the right answer is #a)#

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