Question #a888b Calculus Applications of Definite Integrals Determining the Surface Area of a Solid of Revolution 1 Answer Narad T. Oct 22, 2017 The answer is #=2# Explanation: We need #intcosxdx=sinx+C# #intsin2xdx=-1/2cos2x+C# Therefore, #int_0 ^(pi/2)(cosx+sin2x)=[sinx-1/2cos2x]_0^(pi/2)# #=(sin(pi/2)-1/2cospi)-(sin0-1/2cos0)# #=1+1/2-0+1/2# #=2# Answer link Related questions How do you find the surface area of a solid of revolution? How do you find the surface area of the solid obtained by rotating about the #y#-axis the region... How do you find the surface area of the solid obtained by rotating about the #x#-axis the region... How do you find the surface area of the solid obtained by rotating about the #x#-axis the region... How do you find the surface area of the solid obtained by rotating about the #y#-axis the region... How do you find the surface area of the solid obtained by rotating about the #x#-axis the region... How do you find the surface area of the solid obtained by rotating about the #x#-axis the region... How do you find the surface area of the part of the circular paraboloid #z=x^2+y^2# that lies... How do you determine the surface area of a solid revolved about the x-axis? How do you find the centroid of the quarter circle of radius 1 with center at the origin lying... See all questions in Determining the Surface Area of a Solid of Revolution Impact of this question 1346 views around the world You can reuse this answer Creative Commons License