What is the derivative of #(1-sinx)/cosx #?
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1 Answer
Mar 20, 2017
# dy/dx = secxtanx - sec^2x#
Explanation:
We have:
# y = (1-sinx)/cosx #
# \ \ = 1/cosx - sinx/cosx#
Differentiating wrt
# dy/dx = secx - tanx#
# \ \ \ \ \ = secxtanx - sec^2x#
