Question #b6ebc
1 Answer
We know that minimum energy required to eject an electron from the surface is called the photoelectric work function
In case the wave-length
As such we have the expression
#hc/lambda=phi_0+E_(k_max)# .......(1)
where#h# is Planck's Constant#=6.626xx10^-34" J"cdot"s"#
or#=4.136xx10^-15" eV"cdot"s"# ,#c# is Velocity of light in vacuum#=3xx10^8" m"cdot"s"^-2#
also#phi_0=hc/lambda_0# .......(2)
(a) Using the given and stated values we get work function for tungsten as
(b) Using equation (2) we get
.-.-.-.-.-.-.-.-.-.-.-.
We have made use of Einstein's equation for energy of a photon
and wave equation
to write expression for energy of a photon as