Question #1b68f

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Answer 1 · 2017-04-06T14:49:28

#dy/dx=-x/sqrt(tan(a^2)-x^2)#

Applying #tan# to both sides

#x^2+y^2=tan(a^2)#

now deriving

#2xdx+2ydy=0# or

#dy/dx = -x/y#

but

#y = sqrt(tan(a^2)-x^2)#

so finally

#dy/dx=-x/sqrt(tan(a^2)-x^2)#