Question

Question #12f8c

Answer 1

`pi/3`. `pi`, and `(5pi)/3`, if you meant to leave out the `0`. If you want all the critical numbers on a full period, then include `0` or `2pi`.

Explanation:

`f'(x) = 2sinxcosx-sinx = sinx(2cosx-1)`

#f'(x) is nevern undefined and

`f'(x) = 0` at

`sinx = 0` or `cosx = 1/2`.

This leads to solutions `x=0`, `x=pi`, `x=pi/3` and `x=(5pi)/3`