What is the de Broglie wavelength for a #"0.01 kg"# particle moving at #"10 m/s"#"?
1 Answer
Apr 15, 2017
I got:
Explanation:
We know that the deBroglie wavelength is:
#lambda=h/p#
where:
#h=6.63xx10^-34# #"J"cdot"s"# is Planck's constant;#p=mv# is the linear momentum.
We get:
#lambda=(6.63xx10^-34)/(0.01*10)=6.63xx10^-33# #"m"# ,
too small to be detected by any device.
This is indicative of a large, non-quantum system.