A volume of 20*cm^320⋅cm3 acetylene was combusted with a volume of 500*cm^3500⋅cm3 dioxygen in a piston. What is the end volume of the gases confined by the piston?

1 Answer
anor277
Aug 29, 2017

Good question......I gets an end volume of 490*cm^3490⋅cm3

Explanation:

We gots the combustion equation.....

HC-=CH(g) + 5/2O_2(g) rarr 2CO_2(g) +H_2O(l)+Delta

I use the half-integral coefficient because I think the arithmetic is easier in this way. Is it balanced? It is your problem not mine.

And so we start with 20*cm^3 acetylene, which required 50*cm^3 of dioxygen, and gives 40*cm^3 carbon dioxide gas upon complete combustion. I assume that the water has condensed. Agreed?

And so to begin we had a (20_"acetylene"+500_"dioxygen")*cm^3 volume of gas.....

To end we had ............ (520_"starting volume"-50_"dioxygen"-20_"acetylene"+40_(CO_2))*cm^3=490*cm^3

Do you agree? All care taken but no responsibility admitted.

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