Question #b292b

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Question #b292b

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Answer 1 · 2017-04-26T17:43:16

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Explanation:

The balanced equation is

$2 N a B r + M {g (N O_{3})}_{2} \to 2 N a N O_{3} + M g B r_{2}$ $2NaBr+Mg(NO_3)_2 rarr 2NaNO_3 + Mg Br_2$

In ionic form, this would be

$2 N a^{+} + 2 B r^{-}$ $2 Na^+ + 2Br^-$ $+ M g^{2 +} + 2 N O_{3}^{-}$ $+ Mg^(2+) + 2 NO_3^-$ $\to 2 N a^{+} + 2 N O_{3}^{-}$ $rarr 2 Na^+ + 2NO_3^-$ $+ M g^{2 +} + 2 B r^{-}$ $+ Mg^(2+) + 2 Br^-$

There is no net ionic equation really, because there is no reaction among these species. (All substances formed are soluble.) The net ionic equation would result in complete cancellation of all ions.

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Question #b292b

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